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Berapa Volume dan Luas Permukaan Limas Segiempat tersebut?

Jelaskan jawabanmu menggunakan caramu sendiri.


Selanjutnya

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10 komentar:

  1. Wijaya Teduh23 Mei 2023 pukul 09.23

    Dipisahkan luas permukaan dan volumenya

    BalasHapus
  2. Muhammad Zendi24 Mei 2023 pukul 19.34

    Nama: Muhammad Zendi Romadon
    Kelas : 8C
    Jawban:
    L= L alas × L sisi tegak
    =P×l+2×1/2×a×t+2×1/2×a×c
    =12×16+2×1/2×16×4√109+2×1/2×4√29×12
    =192+64√109+48√29

    BalasHapus
  3. Anonim28 Mei 2023 pukul 12.29

    Nama:Amira sofiani
    kelas:8b
    jawaban:L= L alasx L sisi tegak
    =pxl+2x1/2xaxt+2x1/2xa
    =12x16+2+1/2x16x4√109+2x1/2x4√29x12=192+64√109+48√29cm²
    volume=1280cm³

    BalasHapus
  4. Anonim28 Mei 2023 pukul 12.29

    Nama:Aisah Rahma Afriza
    Kelas:8b
    Jawaban:
    L=L alas × L sisi tegak
    =P×l+2×1/2×a×t+2×1/2×a
    =12×16+2×1/2×16×4√109+2×1/2×4√29×12
    =192+64√109+48√29cm²

    Volume=1.280cm³

    BalasHapus
  5. Anonim28 Mei 2023 pukul 13.24

    Nama: Icha Eka
    Kelas: 8b
    Jawaban:L=L alas × L sisi tegak
    =P×l+2×1/2×a×t+2×1/2×a
    =12×16+2×1/2×16×4√109+2×1/2×4√29×12
    =192+64√109+48√29cm²

    Volume= 1.280cm²

    BalasHapus
  6. Anonim29 Mei 2023 pukul 19.08

    Nama: Talitha Hasna Wardani
    Kelas:8b
    Jawaban: L=L alas × L sisi tegak
    =P×l+2×1/2×a×t+2×1/2×a
    =12×16+2×1/2×16×4√109+2×1/2×4√29×12
    =192+64√109+48√29cm²

    Volume= 1.280cm²

    BalasHapus
  7. M. RAISAA AI FIRDAUS2 Juni 2023 pukul 19.50

    Nama:Muhammad Raissa Al-Firdaus
    Kelas:8C
    Jawaban:L=L alas×L sis tegak
    =P×l+2×1/2×a×t+2×1/2×a
    =12×16+2×1/2×16×4√109+2×1/2×4√29×12
    =192+64√109+48√29cm²

    Volume=1.280cm²

    BalasHapus
  8. Anonim4 Juni 2023 pukul 20.56

    Nama:SIFA RAGIL SAPUTRI
    Kelas:8B
    Jawab:Jawaban: L=L alas × L sisi tegak
    =P×l+2×1/2×a×t+2×1/2×a
    =12×16+2×1/2×16×4√109+2×1/2×4√29×12
    =192+64√109+48√29cm²

    Volume= 1.280cm²

    BalasHapus
  9. Anonim6 Juni 2023 pukul 00.17

    Nama: Ratna Dzumilah Prabaningrum
    Kelas:8C
    Jawaban:
    V = 1/3 x L. Alas x t
    V= 1/3 x (12 x 16) x 20
    V= 1.280 cm³

    L. Permukaan limas
    = (L. Alas) + (L. Sisi tegak)
    = (12 x16) + (4 x 1/2 x 12 x 16 x 20)
    =192 + (7.680)
    =7.872 cm²

    BalasHapus
  10. Anonim6 Juni 2023 pukul 11.49

    nama : alimah Sani
    kelas : 8a
    jawaban : p×l+2×1/2×a×t+2×1/2×a
    =12×16+2×1/2×16×4√109+2×1/2×4√29×12
    =192+64√109+48√29cm²
    volume = 1.280cm²

    BalasHapus

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